Easy
Explain the delocalization of electrons in $CH_3-CH_2^+$ and $CH_3-CH=CH_2$.
(N/A) In $CH_3-CH_2^+$,the $\sigma$-orbital of the $C-H$ bond of the $CH_3$ group and the vacant $2p$-orbital of the $CH_2^+$ group are parallel,which allows for the delocalization of $\sigma$-electrons into the vacant $p$-orbital (hyperconjugation).
In $CH_3-CH=CH_2$,the $\sigma$-orbital of the $C-H$ bond of the $CH_3$ group and the $2p$-orbitals of the $\pi$-bond of the $CH=CH_2$ group are parallel,allowing for the delocalization of $\sigma$-electrons into the $\pi$-system (hyperconjugation).
In $CH_3-CH=CH_2$,the $\sigma$-orbital of the $C-H$ bond of the $CH_3$ group and the $2p$-orbitals of the $\pi$-bond of the $CH=CH_2$ group are parallel,allowing for the delocalization of $\sigma$-electrons into the $\pi$-system (hyperconjugation).
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View SolutionGiven below are two statements:
Statement $I$: On the basis of inductive effect, the order of stability of alkyl carbanions is $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$.
Statement $II$: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.
Statement $I$: On the basis of inductive effect, the order of stability of alkyl carbanions is $CH_3^- > CH_3CH_2^- > (CH_3)_2CH^- > (CH_3)_3C^-$.
Statement $II$: Allyl and benzyl carbanions are more stabilised by inductive effect and not by resonance effect.
State True or False for the following statements:
$(i)$ The stability of carbocation is explained by the delocalized structure of hyperconjugation.
$(ii)$ The stability of carbocation is explained by drawing the resonance structure.
$(iii)$ Hyperconjugation effect is $(+)$ or $(-)$.
$(iv)$ Mesomeric effect is $(+)$ or $(-)$.
$(i)$ The stability of carbocation is explained by the delocalized structure of hyperconjugation.
$(ii)$ The stability of carbocation is explained by drawing the resonance structure.
$(iii)$ Hyperconjugation effect is $(+)$ or $(-)$.
$(iv)$ Mesomeric effect is $(+)$ or $(-)$.
Easy
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